#2179
Max3
Fie n
un număr natural nenul şi un şir de n
numere naturale nenule, fiecare număr din şir având cel mult 3
cifre. Şirul dat se „maximizează”
prin aplicarea următoarelor transformări:
ONI GIM 2010
Problema | Max3 | Operații I/O |
![]() max3.in /max3.out
|
---|---|---|---|
Limita timp | 1 secunde | Limita memorie |
Total: 64 MB
/
Stivă 8 MB
|
Id soluție | #57105772 | Utilizator | |
Fișier | max3.cpp | Dimensiune | 442 B |
Data încărcării | 16 Martie 2025, 20:57 | Scor / rezultat | Eroare de compilare |
max3.cpp: In function 'int main()': max3.cpp:14:3: error: 'd' was not declared in this scope d=x%10; ^ max3.cpp:15:3: error: 't' was not declared in this scope t=xx/100; ^ max3.cpp:16:6: error: 'p' was not declared in this scope if(p<d){aux=p;p=d;d=aux;} ^ max3.cpp:16:11: error: 'aux' was not declared in this scope if(p<d){aux=p;p=d;d=aux;} ^ max3.cpp:17:6: error: 'p' was not declared in this scope if(p<t){aux=p;p=t;t=aux;} ^ max3.cpp:17:11: error: 'aux' was not declared in this scope if(p<t){aux=p;p=t;t=aux;} ^ max3.cpp:18:11: error: 'aux' was not declared in this scope if(d<t){aux=d;p=t;t=aux;} ^ max3.cpp:18:17: error: 'p' was not declared in this scope if(d<t){aux=d;p=t;t=aux;} ^ max3.cpp:20:8: error: 'p' was not declared in this scope maxx=p*10+d*10+t; ^ max3.cpp:20:13: error: 'd' was not declared in this scope maxx=p*10+d*10+t; ^ max3.cpp:20:18: error: 't' was not declared in this scope maxx=p*10+d*10+t; ^ max3.cpp:7:23: warning: unused variable 'uc' [-Wunused-variable] {long long n,maxx,x,i,uc,xx,xxx,mxx; ^ max3.cpp:7:29: warning: unused variable 'xxx' [-Wunused-variable] {long long n,maxx,x,i,uc,xx,xxx,mxx; ^ max3.cpp:7:33: warning: unused variable 'mxx' [-Wunused-variable] {long long n,maxx,x,i,uc,xx,xxx,mxx; ^
www.pbinfo.ro permite evaluarea a două tipuri de probleme:
Problema Max3 face parte din prima categorie. Soluția propusă de tine va fi evaluată astfel:
Suma punctajelor acordate pe testele utilizate pentru verificare este 100. Astfel, soluția ta poate obține cel mult 100 de puncte, caz în care se poate considera corectă.